SQLServer RANK()排名函数如何使用 - 开发技术
今天小编给大家分享一下SQLServer RANK()排名函数如何使用的相关知识点,内容详细,逻辑清晰,相信大部分人都还太了解这方面的知识,所以分享这篇文章给大家参考一下,希望大家阅读完这篇文章后有所收获,下面我们一起来了解一下吧。
具体如下:
-- 例子表数据 SELECT * FROM test; -- 统计分数 SELECT name,SUM(achievement) achievement FROM test GROUP BY name; -- 按统计分数做排行 SELECT RANK() OVER( ORDER BY SUM(achievement) desc) 排行,name,SUM(achievement) achievement FROM test GROUP BY name;
求助问答存储过程使用:
USE [DB] GO /****** Object: StoredProcedure [dbo].[sp_TodayJoinUser] Script Date: 2021/1/26 14:45:24 ******/ SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO -- ============================================= -- Author: _Hey_Jude -- Create date: 2021-01-26 -- Description: 获取今日发表帮助/回复的新用户 -- ============================================= CREATE PROCEDURE [dbo].[sp_TodayJoinUser] @tableLevel int, @date varchar(30) AS Declare @Sql nvarchar(max) declare @minTabId int declare @maxTabId int declare @maxf_id int declare @helpTableName nvarchar(max) declare @tableCount int BEGIN --最小f_id所在表 set @minTabId=0 set @tableCount=@minTabId --最大f_id所在表 set @maxf_id=(select MAX(F_ID) from [Table] where F_IsDelete=0) set @maxTabId=@maxf_id/@tablelevel set @helpTableName='SELECT UserID, Max([F_DateTime]) AS dt FROM [Table] GROUP BY UserID' while @tableCount<=@maxTabId begin print @tableCount set @helpTableName += ' UNION SELECT UserID, Max([DateTime]) as dt FROM SubTable'+cast(@tableCount as nvarchar(10))+' GROUP BY UserID ' set @tableCount=@tableCount+1 end set @Sql='SELECT [nikename] FROM ( SELECT UserID, RANK() OVER(PARTITION BY UserID ORDER BY dt) AS Num,dt FROM ( '+@helpTableName+' ) AS T ) AS NewT LEFT JOIN [UserTable] A WITH(NOLOCK) ON NewT.UserID = A.UserId WHERE Num = 1 AND dt > '''+@date+'''' Exec sp_executesql @Sql END GO
partition的意思是对数据进行分区,sql语句如下
SELECT* FROM ( SELECT ROW_NUMBER() over(partition by [姓名] order by [打卡时间] desc) as rowNum, [姓名], [打卡时间] FROM [dbo].[打卡记录表] ) temp WHERE temp.rowNum = 1
通过 partition by [姓名] order by [打卡时间] desc,这句就可以做到,让数据按照姓名分组,并且在每组内部按照时间进行排序
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发布于:2023-01-18,除非注明,否则均为
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